What are the solutions to the equation -5x^2=-8 ?

The solutions to the equation -5x^2=-8 are x=(2sqrt(2))/(sqrt(5)),x=-(2sqrt(2))/(sqrt(5))

Find the zeros of -5x^2=-8

The zeros of -5x^2=-8 are x=(2sqrt(2))/(sqrt(5)),x=-(2sqrt(2))/(sqrt(5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 5 x^{2} = - 8

x = \frac{2 2}{5}, x = - \frac{2 2}{5}

Decimal Notation

x = 1.26491 \dots, x = - 1.26491 \dots

Solution steps

- 5 x^{2} = - 8

Divide both sides by

- 5

x^{2} = \frac{8}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{8}{5}, x = - \frac{8}{5}

\frac{8}{5} = \frac{2 2}{5}

- \frac{8}{5} = - \frac{2 2}{5}

x = \frac{2 2}{5}, x = - \frac{2 2}{5}

0 = 2 x^{2} - 7 x - 4

p^{2} - 2 = - 9

x, f (x - 2) f = x^{2} + 5

10 = x^{2} - 4 x + 1

b x^{2} + b x - x = 0

What are the solutions to the equation -5x^2=-8 ?
The solutions to the equation -5x^2=-8 are x=(2sqrt(2))/(sqrt(5)),x=-(2sqrt(2))/(sqrt(5))
Find the zeros of -5x^2=-8
The zeros of -5x^2=-8 are x=(2sqrt(2))/(sqrt(5)),x=-(2sqrt(2))/(sqrt(5))