What are the solutions to the equation -2x^2-10x+12=0 ?

The solutions to the equation -2x^2-10x+12=0 are x=-6,x=1

Find the zeros of -2x^2-10x+12=0

The zeros of -2x^2-10x+12=0 are x=-6,x=1

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- 2 x^{2} - 10 x + 12 = 0

x = - 6, x = 1

Solution steps

- 2 x^{2} - 10 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 ( - 2 ) \cdot 12}{2 ( - 2 )}

(- 10)^{2} - 4 (- 2) \cdot 12 = 14

x_{1, 2} = \frac{- ( - 10 ) \pm 14}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 14}{2 ( - 2 )}, x_{2} = \frac{- ( - 10 ) - 14}{2 ( - 2 )}

x = \frac{- ( - 10 ) + 14}{2 ( - 2 )} : - 6

x = \frac{- ( - 10 ) - 14}{2 ( - 2 )} : 1

The solutions to the quadratic equation are:

x = - 6, x = 1

\frac{1}{2} x + 1 = x^{2} - 2 x + 1

v, F = \frac{h M v ^{2}}{r}

x (x + 1)^{2} = (x - 1)^{3}

x^{2} + 4 x + 12 = - 2 x + 4

x^{2} - 7 x + 6 = 0

What are the solutions to the equation -2x^2-10x+12=0 ?
The solutions to the equation -2x^2-10x+12=0 are x=-6,x=1
Find the zeros of -2x^2-10x+12=0
The zeros of -2x^2-10x+12=0 are x=-6,x=1