What are the solutions to the equation 46x+7x^2=21 ?

The solutions to the equation 46x+7x^2=21 are x= 3/7 ,x=-7

Find the zeros of 46x+7x^2=21

The zeros of 46x+7x^2=21 are x= 3/7 ,x=-7

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46 x + 7 x^{2} = 21

x = \frac{3}{7}, x = - 7

Decimal Notation

x = 0.42857 \dots, x = - 7

Solution steps

46 x + 7 x^{2} = 21

Move

21

to the left side

46 x + 7 x^{2} - 21 = 0

Write in the standard form

a x^{2} + b x + c = 0

7 x^{2} + 46 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 46 \pm 4 6 ^{2} - 4 \cdot 7 ( - 21 )}{2 \cdot 7}

4 6^{2} - 4 \cdot 7 (- 21) = 52

x_{1, 2} = \frac{- 46 \pm 52}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 46 + 52}{2 \cdot 7}, x_{2} = \frac{- 46 - 52}{2 \cdot 7}

x = \frac{- 46 + 52}{2 \cdot 7} : \frac{3}{7}

x = \frac{- 46 - 52}{2 \cdot 7} : - 7

The solutions to the quadratic equation are:

x = \frac{3}{7}, x = - 7

3.14 \cdot x^{2} = 4

2 x^{2} + 28 x + 1

x, f (x - 2) = x^{2} + 8 x + 5

(z - 16)^{2} = 144

5 x = 15 x^{2}

What are the solutions to the equation 46x+7x^2=21 ?
The solutions to the equation 46x+7x^2=21 are x= 3/7 ,x=-7
Find the zeros of 46x+7x^2=21
The zeros of 46x+7x^2=21 are x= 3/7 ,x=-7