What are the solutions to the equation (y-6)^2-4=14 ?

The solutions to the equation (y-6)^2-4=14 are y=3sqrt(2)+6,y=-3sqrt(2)+6

Find the zeros of (y-6)^2-4=14

The zeros of (y-6)^2-4=14 are y=3sqrt(2)+6,y=-3sqrt(2)+6

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(y - 6)^{2} - 4 = 14

y = 32 + 6, y = - 32 + 6

Decimal Notation

y = 10.24264 \dots, y = 1.75735 \dots

Solution steps

(y - 6)^{2} - 4 = 14

Move

4

to the right side

(y - 6)^{2} = 18

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y - 6 = 18 : y = 32 + 6

Solve

y - 6 = - 18 : y = - 32 + 6

The solutions to the quadratic equation are:

y = 32 + 6, y = - 32 + 6

3 x^{2} - 27 = 0

(2 x + 3)^{2} = 6

u^{2} + u - 30 = 0

2 x^{2} - 9 x = - 7

2 x^{2} - 9 x = - 9

What are the solutions to the equation (y-6)^2-4=14 ?
The solutions to the equation (y-6)^2-4=14 are y=3sqrt(2)+6,y=-3sqrt(2)+6
Find the zeros of (y-6)^2-4=14
The zeros of (y-6)^2-4=14 are y=3sqrt(2)+6,y=-3sqrt(2)+6