What are the solutions to the equation 3(x-6)^2+4=0 ?

The solutions to the equation 3(x-6)^2+4=0 are x=6+i(2sqrt(3))/3 ,x=6-i(2sqrt(3))/3

Find the zeros of 3(x-6)^2+4=0

The zeros of 3(x-6)^2+4=0 are x=6+i(2sqrt(3))/3 ,x=6-i(2sqrt(3))/3

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3 (x - 6)^{2} + 4 = 0

x = 6 + i \frac{2 3}{3}, x = 6 - i \frac{2 3}{3}

Solution steps

3 (x - 6)^{2} + 4 = 0

Move

4

to the right side

3 (x - 6)^{2} = - 4

Divide both sides by

3

(x - 6)^{2} = - \frac{4}{3}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 6 = - \frac{4}{3} : x = 6 + i \frac{2 3}{3}

Solve

x - 6 = - - \frac{4}{3} : x = 6 - i \frac{2 3}{3}

The solutions to the quadratic equation are:

x = 6 + i \frac{2 3}{3}, x = 6 - i \frac{2 3}{3}

lo g_{3} (81) = x^{2}

3 n^{2} - 4 n + 9 = 3

5 (x - 3)^{2} = 20

x^{2} + 8 + 12 = 0

(y - 1)^{2} - (y - 2)^{2} = y^{2}

What are the solutions to the equation 3(x-6)^2+4=0 ?
The solutions to the equation 3(x-6)^2+4=0 are x=6+i(2sqrt(3))/3 ,x=6-i(2sqrt(3))/3
Find the zeros of 3(x-6)^2+4=0
The zeros of 3(x-6)^2+4=0 are x=6+i(2sqrt(3))/3 ,x=6-i(2sqrt(3))/3