What are the solutions to the equation 0=y(4-y) ?

The solutions to the equation 0=y(4-y) are y=0,y=4

Find the zeros of 0=y(4-y)

The zeros of 0=y(4-y) are y=0,y=4

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0 = y (4 - y)

y = 0, y = 4

Solution steps

0 = y (4 - y)

Switch sides

y (4 - y) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or 4 - y = 0

Solve

4 - y = 0 : y = 4

The solutions to the quadratic equation are:

y = 0, y = 4

x, f (h (x)) = x^{2} + 7

x^{2} = 1^{2} + 4^{2}

2 x^{2} + 5 x - 8 = 0

6 x^{2} - 17 x = - 12

6 t^{2} - t - 2 = 0

What are the solutions to the equation 0=y(4-y) ?
The solutions to the equation 0=y(4-y) are y=0,y=4
Find the zeros of 0=y(4-y)
The zeros of 0=y(4-y) are y=0,y=4