What are the solutions to the equation 4a^2-16a+16=36a-144 ?

The solutions to the equation 4a^2-16a+16=36a-144 are a=8,a=5

Find the zeros of 4a^2-16a+16=36a-144

The zeros of 4a^2-16a+16=36a-144 are a=8,a=5

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4 a^{2} - 16 a + 16 = 36 a - 144

a = 8, a = 5

Solution steps

4 a^{2} - 16 a + 16 = 36 a - 144

Move

144

to the left side

4 a^{2} - 16 a + 160 = 36 a

Move

36 a

to the left side

4 a^{2} - 52 a + 160 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 52 ) \pm ( - 52 ) ^{2} - 4 \cdot 4 \cdot 160}{2 \cdot 4}

(- 52)^{2} - 4 \cdot 4 \cdot 160 = 12

a_{1, 2} = \frac{- ( - 52 ) \pm 12}{2 \cdot 4}

Separate the solutions

a_{1} = \frac{- ( - 52 ) + 12}{2 \cdot 4}, a_{2} = \frac{- ( - 52 ) - 12}{2 \cdot 4}

a = \frac{- ( - 52 ) + 12}{2 \cdot 4} : 8

a = \frac{- ( - 52 ) - 12}{2 \cdot 4} : 5

The solutions to the quadratic equation are:

a = 8, a = 5

4 x^{2} = 27 x + 7

20 = - 16 t^{2} + 100 t + 5

4 w (w + 3) + 15 = 0

- 4 x^{2} + 64 x - 252 = 0

x^{2} = - 14 + 9 x

What are the solutions to the equation 4a^2-16a+16=36a-144 ?
The solutions to the equation 4a^2-16a+16=36a-144 are a=8,a=5
Find the zeros of 4a^2-16a+16=36a-144
The zeros of 4a^2-16a+16=36a-144 are a=8,a=5