What are the solutions to the equation -3x^2-5x=-1 ?

The solutions to the equation -3x^2-5x=-1 are x=-(5+sqrt(37))/6 ,x=(sqrt(37)-5)/6

Find the zeros of -3x^2-5x=-1

The zeros of -3x^2-5x=-1 are x=-(5+sqrt(37))/6 ,x=(sqrt(37)-5)/6

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- 3 x^{2} - 5 x = - 1

x = - \frac{5 + 37}{6}, x = \frac{37 - 5}{6}

Decimal Notation

x = - 1.84712 \dots, x = 0.18046 \dots

Solution steps

- 3 x^{2} - 5 x = - 1

Move

1

to the left side

- 3 x^{2} - 5 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 3 ) \cdot 1}{2 ( - 3 )}

(- 5)^{2} - 4 (- 3) \cdot 1 = 37

x_{1, 2} = \frac{- ( - 5 ) \pm 37}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 37}{2 ( - 3 )}, x_{2} = \frac{- ( - 5 ) - 37}{2 ( - 3 )}

x = \frac{- ( - 5 ) + 37}{2 ( - 3 )} : - \frac{5 + 37}{6}

x = \frac{- ( - 5 ) - 37}{2 ( - 3 )} : \frac{37 - 5}{6}

The solutions to the quadratic equation are:

x = - \frac{5 + 37}{6}, x = \frac{37 - 5}{6}

x, f (x + 1) = 3 x^{2} - x + 2

5 x = - 8 x^{2} + 10

(- (1 - 2) x)^{2} + x^{2} = 1

l = x^{2} - 8, w (x) = - x + 12

x^{2} - 0.017 x - 0.063 = 0

What are the solutions to the equation -3x^2-5x=-1 ?
The solutions to the equation -3x^2-5x=-1 are x=-(5+sqrt(37))/6 ,x=(sqrt(37)-5)/6
Find the zeros of -3x^2-5x=-1
The zeros of -3x^2-5x=-1 are x=-(5+sqrt(37))/6 ,x=(sqrt(37)-5)/6