What are the solutions to the equation 6x^2+1=10x ?

The solutions to the equation 6x^2+1=10x are x=(5+sqrt(19))/6 ,x=(5-sqrt(19))/6

Find the zeros of 6x^2+1=10x

The zeros of 6x^2+1=10x are x=(5+sqrt(19))/6 ,x=(5-sqrt(19))/6

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6 x^{2} + 1 = 10 x

x = \frac{5 + 19}{6}, x = \frac{5 - 19}{6}

Decimal Notation

x = 1.55981 \dots, x = 0.10685 \dots

Solution steps

6 x^{2} + 1 = 10 x

Move

10 x

to the left side

6 x^{2} + 1 - 10 x = 0

Write in the standard form

a x^{2} + b x + c = 0

6 x^{2} - 10 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 6 \cdot 1}{2 \cdot 6}

(- 10)^{2} - 4 \cdot 6 \cdot 1 = 219

x_{1, 2} = \frac{- ( - 10 ) \pm 2 19}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 19}{2 \cdot 6}, x_{2} = \frac{- ( - 10 ) - 2 19}{2 \cdot 6}

x = \frac{- ( - 10 ) + 2 19}{2 \cdot 6} : \frac{5 + 19}{6}

x = \frac{- ( - 10 ) - 2 19}{2 \cdot 6} : \frac{5 - 19}{6}

The solutions to the quadratic equation are:

x = \frac{5 + 19}{6}, x = \frac{5 - 19}{6}

(x - 7)^{2} - 24 = 1

(- x - 3)^{2} = 0

(x + 3) (x - 1) = 21

2 (x + 6)^{2} = 90

h^{2} = 160

What are the solutions to the equation 6x^2+1=10x ?
The solutions to the equation 6x^2+1=10x are x=(5+sqrt(19))/6 ,x=(5-sqrt(19))/6
Find the zeros of 6x^2+1=10x
The zeros of 6x^2+1=10x are x=(5+sqrt(19))/6 ,x=(5-sqrt(19))/6