What are the solutions to the equation 2m^2+13m-7=0 ?

The solutions to the equation 2m^2+13m-7=0 are m= 1/2 ,m=-7

Find the zeros of 2m^2+13m-7=0

The zeros of 2m^2+13m-7=0 are m= 1/2 ,m=-7

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2 m^{2} + 13 m - 7 = 0

m = \frac{1}{2}, m = - 7

Decimal Notation

m = 0.5, m = - 7

Solution steps

2 m^{2} + 13 m - 7 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 2 ( - 7 )}{2 \cdot 2}

1 3^{2} - 4 \cdot 2 (- 7) = 15

m_{1, 2} = \frac{- 13 \pm 15}{2 \cdot 2}

Separate the solutions

m_{1} = \frac{- 13 + 15}{2 \cdot 2}, m_{2} = \frac{- 13 - 15}{2 \cdot 2}

m = \frac{- 13 + 15}{2 \cdot 2} : \frac{1}{2}

m = \frac{- 13 - 15}{2 \cdot 2} : - 7

The solutions to the quadratic equation are:

m = \frac{1}{2}, m = - 7

x^{2} + x = x

9 + 5 x - x^{2}

(2 x - 7) (3 x - 5) = 0

x, x^{2} (y + 4)^{2} = 25

- 2 (x + 1)^{2} - 4 = 12

What are the solutions to the equation 2m^2+13m-7=0 ?
The solutions to the equation 2m^2+13m-7=0 are m= 1/2 ,m=-7
Find the zeros of 2m^2+13m-7=0
The zeros of 2m^2+13m-7=0 are m= 1/2 ,m=-7