What are the solutions to the equation 8-3(x+4)^2=-424 ?

The solutions to the equation 8-3(x+4)^2=-424 are x=8,x=-16

Find the zeros of 8-3(x+4)^2=-424

The zeros of 8-3(x+4)^2=-424 are x=8,x=-16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8 - 3 (x + 4)^{2} = - 424

x = 8, x = - 16

Solution steps

8 - 3 (x + 4)^{2} = - 424

Move

8

to the right side

- 3 (x + 4)^{2} = - 432

Divide both sides by

- 3

(x + 4)^{2} = 144

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 144 : x = 8

Solve

x + 4 = - 144 : x = - 16

The solutions to the quadratic equation are:

x = 8, x = - 16

3 x^{2} - 12 x - 10 = 0

6 x - 6 = - 5 (x - 1)^{2} - 3 x^{2} + 3

5 x^{2} + 6 x + 7 = 0

(0 + 2)^{2} + (y - 5)^{2} = 25

(a - 7)^{2} + 5 = 55

What are the solutions to the equation 8-3(x+4)^2=-424 ?
The solutions to the equation 8-3(x+4)^2=-424 are x=8,x=-16
Find the zeros of 8-3(x+4)^2=-424
The zeros of 8-3(x+4)^2=-424 are x=8,x=-16