What are the solutions to the equation 6n^2+12n-38=0 ?

The solutions to the equation 6n^2+12n-38=0 are n=(-3+sqrt(66))/3 ,n=-(3+sqrt(66))/3

Find the zeros of 6n^2+12n-38=0

The zeros of 6n^2+12n-38=0 are n=(-3+sqrt(66))/3 ,n=-(3+sqrt(66))/3

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6 n^{2} + 12 n - 38 = 0

n = \frac{- 3 + 66}{3}, n = - \frac{3 + 66}{3}

Decimal Notation

n = 1.70801 \dots, n = - 3.70801 \dots

Solution steps

6 n^{2} + 12 n - 38 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 6 ( - 38 )}{2 \cdot 6}

1 2^{2} - 4 \cdot 6 (- 38) = 466

n_{1, 2} = \frac{- 12 \pm 4 66}{2 \cdot 6}

Separate the solutions

n_{1} = \frac{- 12 + 4 66}{2 \cdot 6}, n_{2} = \frac{- 12 - 4 66}{2 \cdot 6}

n = \frac{- 12 + 4 66}{2 \cdot 6} : \frac{- 3 + 66}{3}

n = \frac{- 12 - 4 66}{2 \cdot 6} : - \frac{3 + 66}{3}

The solutions to the quadratic equation are:

n = \frac{- 3 + 66}{3}, n = - \frac{3 + 66}{3}

- 5 x^{2} - 60 x - 100 = 0

2 x^{2} - 15 = 17

x^{2} - 2 m x + n^{2} = 0

2 m (m - 5) + 10 = 0

x^{2} - 18 x + 21 = - 59

What are the solutions to the equation 6n^2+12n-38=0 ?
The solutions to the equation 6n^2+12n-38=0 are n=(-3+sqrt(66))/3 ,n=-(3+sqrt(66))/3
Find the zeros of 6n^2+12n-38=0
The zeros of 6n^2+12n-38=0 are n=(-3+sqrt(66))/3 ,n=-(3+sqrt(66))/3