What are the solutions to the equation x^2+5x-546=0 ?

The solutions to the equation x^2+5x-546=0 are x=21,x=-26

Find the zeros of x^2+5x-546=0

The zeros of x^2+5x-546=0 are x=21,x=-26

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x^{2} + 5 x - 546 = 0

x = 21, x = - 26

Solution steps

x^{2} + 5 x - 546 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 546 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 546) = 47

x_{1, 2} = \frac{- 5 \pm 47}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 47}{2 \cdot 1}, x_{2} = \frac{- 5 - 47}{2 \cdot 1}

x = \frac{- 5 + 47}{2 \cdot 1} : 21

x = \frac{- 5 - 47}{2 \cdot 1} : - 26

The solutions to the quadratic equation are:

x = 21, x = - 26

m^{2} - 10 m - 25 = 0

(5 x + 6)^{2} = 3

3 x^{2} + 12 x + 2

x^{2} - 2 = x + 4

x, (x - 12) (x + 4) = 9

What are the solutions to the equation x^2+5x-546=0 ?
The solutions to the equation x^2+5x-546=0 are x=21,x=-26
Find the zeros of x^2+5x-546=0
The zeros of x^2+5x-546=0 are x=21,x=-26