What are the solutions to the equation y^2-12y+25=0 ?

The solutions to the equation y^2-12y+25=0 are y=6+sqrt(11),y=6-sqrt(11)

Find the zeros of y^2-12y+25=0

The zeros of y^2-12y+25=0 are y=6+sqrt(11),y=6-sqrt(11)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} - 12 y + 25 = 0

y = 6 + 11, y = 6 - 11

Decimal Notation

y = 9.31662 \dots, y = 2.68337 \dots

Solution steps

y^{2} - 12 y + 25 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 25 = 211

y_{1, 2} = \frac{- ( - 12 ) \pm 2 11}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 12 ) + 2 11}{2 \cdot 1}, y_{2} = \frac{- ( - 12 ) - 2 11}{2 \cdot 1}

y = \frac{- ( - 12 ) + 2 11}{2 \cdot 1} : 6 + 11

y = \frac{- ( - 12 ) - 2 11}{2 \cdot 1} : 6 - 11

The solutions to the quadratic equation are:

y = 6 + 11, y = 6 - 11

- 0.018 q^{2} - 12 q + 510 = 0

4 x^{2} - 2 x = - 6

2 (x + 1)^{2} - 8 = 120

- 30 m^{2} + 65 m + 40 = 0

x^{2} + 5 = 9 x

What are the solutions to the equation y^2-12y+25=0 ?
The solutions to the equation y^2-12y+25=0 are y=6+sqrt(11),y=6-sqrt(11)
Find the zeros of y^2-12y+25=0
The zeros of y^2-12y+25=0 are y=6+sqrt(11),y=6-sqrt(11)