What are the solutions to the equation m^2+2m-7=0 ?

The solutions to the equation m^2+2m-7=0 are m=-1+2sqrt(2),m=-1-2sqrt(2)

Find the zeros of m^2+2m-7=0

The zeros of m^2+2m-7=0 are m=-1+2sqrt(2),m=-1-2sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

m^{2} + 2 m - 7 = 0

m = - 1 + 22, m = - 1 - 22

Decimal Notation

m = 1.82842 \dots, m = - 3.82842 \dots

Solution steps

m^{2} + 2 m - 7 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 7) = 42

m_{1, 2} = \frac{- 2 \pm 4 2}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 2 + 4 2}{2 \cdot 1}, m_{2} = \frac{- 2 - 4 2}{2 \cdot 1}

m = \frac{- 2 + 4 2}{2 \cdot 1} : - 1 + 22

m = \frac{- 2 - 4 2}{2 \cdot 1} : - 1 - 22

The solutions to the quadratic equation are:

m = - 1 + 22, m = - 1 - 22

z^{2} - 16 z + 61 = 2 z \cdot 20

x^{2} - 4 x - 15 = 18

x^{2} = 2 a^{2}

9 x^{2} - 36 + 32

18 x^{2} - 12 m x + (6 m - 2) = 0

What are the solutions to the equation m^2+2m-7=0 ?
The solutions to the equation m^2+2m-7=0 are m=-1+2sqrt(2),m=-1-2sqrt(2)
Find the zeros of m^2+2m-7=0
The zeros of m^2+2m-7=0 are m=-1+2sqrt(2),m=-1-2sqrt(2)