What are the solutions to the equation 0=x^2+5x-14 ?

The solutions to the equation 0=x^2+5x-14 are x=2,x=-7

Find the zeros of 0=x^2+5x-14

The zeros of 0=x^2+5x-14 are x=2,x=-7

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0 = x^{2} + 5 x - 14

x = 2, x = - 7

Solution steps

0 = x^{2} + 5 x - 14

Switch sides

x^{2} + 5 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 14) = 9

x_{1, 2} = \frac{- 5 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 9}{2 \cdot 1}, x_{2} = \frac{- 5 - 9}{2 \cdot 1}

x = \frac{- 5 + 9}{2 \cdot 1} : 2

x = \frac{- 5 - 9}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 2, x = - 7

x^{2} = 12 x - 32

y, s (y) = 5 yy + 7

1 - 4 x - 2 x^{2}

(1 - 2 x - x^{2}) = 0

t^{2} = - 3 t - 4

What are the solutions to the equation 0=x^2+5x-14 ?
The solutions to the equation 0=x^2+5x-14 are x=2,x=-7
Find the zeros of 0=x^2+5x-14
The zeros of 0=x^2+5x-14 are x=2,x=-7