What are the solutions to the equation 4x^2=9x+28 ?

The solutions to the equation 4x^2=9x+28 are x=4,x=-7/4

Find the zeros of 4x^2=9x+28

The zeros of 4x^2=9x+28 are x=4,x=-7/4

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4 x^{2} = 9 x + 28

x = 4, x = - \frac{7}{4}

Decimal Notation

x = 4, x = - 1.75

Solution steps

4 x^{2} = 9 x + 28

Move

28

to the left side

4 x^{2} - 28 = 9 x

Move

9 x

to the left side

4 x^{2} - 28 - 9 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 9 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 4 ( - 28 )}{2 \cdot 4}

(- 9)^{2} - 4 \cdot 4 (- 28) = 23

x_{1, 2} = \frac{- ( - 9 ) \pm 23}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 23}{2 \cdot 4}, x_{2} = \frac{- ( - 9 ) - 23}{2 \cdot 4}

x = \frac{- ( - 9 ) + 23}{2 \cdot 4} : 4

x = \frac{- ( - 9 ) - 23}{2 \cdot 4} : - \frac{7}{4}

The solutions to the quadratic equation are:

x = 4, x = - \frac{7}{4}

x^{2} + 3 x + 8 = 0

6 x^{(2)} + 5 = 17 x

a, a^{2} b + c = 24

3 v^{2} - 18 v - 12 = 2

0 = x^{2} + 5 x + 17

What are the solutions to the equation 4x^2=9x+28 ?
The solutions to the equation 4x^2=9x+28 are x=4,x=-7/4
Find the zeros of 4x^2=9x+28
The zeros of 4x^2=9x+28 are x=4,x=-7/4