What are the solutions to the equation -6x+5x^2=-8 ?

The solutions to the equation -6x+5x^2=-8 are x= 3/5+i(sqrt(31))/5 ,x= 3/5-i(sqrt(31))/5

Find the zeros of -6x+5x^2=-8

The zeros of -6x+5x^2=-8 are x= 3/5+i(sqrt(31))/5 ,x= 3/5-i(sqrt(31))/5

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- 6 x + 5 x^{2} = - 8

x = \frac{3}{5} + i \frac{31}{5}, x = \frac{3}{5} - i \frac{31}{5}

Solution steps

- 6 x + 5 x^{2} = - 8

Move

8

to the left side

- 6 x + 5 x^{2} + 8 = 0

Write in the standard form

a x^{2} + b x + c = 0

5 x^{2} - 6 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 5 \cdot 8}{2 \cdot 5}

Simplify

(- 6)^{2} - 4 \cdot 5 \cdot 8 : 231 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 31 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 31 i}{2 \cdot 5}, x_{2} = \frac{- ( - 6 ) - 2 31 i}{2 \cdot 5}

x = \frac{- ( - 6 ) + 2 31 i}{2 \cdot 5} : \frac{3}{5} + i \frac{31}{5}

x = \frac{- ( - 6 ) - 2 31 i}{2 \cdot 5} : \frac{3}{5} - i \frac{31}{5}

The solutions to the quadratic equation are:

x = \frac{3}{5} + i \frac{31}{5}, x = \frac{3}{5} - i \frac{31}{5}

x, 5 x^{2} + 5 y^{2} = 0

n, x = \frac{n ( n + 1 )}{2}

4.905 t^{2} - 25.11 t + 11 = 0

4 x^{2} + 21 x + 27 = 0

3 + x (x - 2) = 6 (x - 2)

What are the solutions to the equation -6x+5x^2=-8 ?
The solutions to the equation -6x+5x^2=-8 are x= 3/5+i(sqrt(31))/5 ,x= 3/5-i(sqrt(31))/5
Find the zeros of -6x+5x^2=-8
The zeros of -6x+5x^2=-8 are x= 3/5+i(sqrt(31))/5 ,x= 3/5-i(sqrt(31))/5