What is factor 3x^4-16x^3+14x^2+24x-9 ?

The solution to factor 3x^4-16x^3+14x^2+24x-9 is (x+1)(3x-1)(x-3)^2

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factor 3x^4-16x^3+14x^2+24x-9

factor

3 x^{4} - 16 x^{3} + 14 x^{2} + 24 x - 9

(x + 1) (3 x - 1) (x - 3)^{2}

Solution steps

3 x^{4} - 16 x^{3} + 14 x^{2} + 24 x - 9

Use the rational root theorem

= (x + 1) \frac{3 x ^{4} - 16 x ^{3} + 14 x ^{2} + 24 x - 9}{x + 1}

\frac{3 x ^{4} - 16 x ^{3} + 14 x ^{2} + 24 x - 9}{x + 1} = 3 x^{3} - 19 x^{2} + 33 x - 9

= (x + 1) (3 x^{3} - 19 x^{2} + 33 x - 9)

Factor

3 x^{3} - 19 x^{2} + 33 x - 9 : (3 x - 1) (x - 3) (x - 3)

= (x + 1) (3 x - 1) (x - 3) (x - 3)

Apply exponent rule:

aa = a^{2}

(x - 3) (x - 3) = (x - 3)^{2}

= (x + 1) (3 x - 1) (x - 3)^{2}

x < 2 - x

(- \frac{5}{x})^{2}

(3 + - 5) (7 - - 10)

x^{2} - 18 x + 45 = 0

3 x^{2} + 3 x - 6 = 0

What is factor 3x^4-16x^3+14x^2+24x-9 ?
The solution to factor 3x^4-16x^3+14x^2+24x-9 is (x+1)(3x-1)(x-3)^2