What are the solutions to the equation 2x^2-9x=7x-64 ?

The solutions to the equation 2x^2-9x=7x-64 are x=4+4i,x=4-4i

Find the zeros of 2x^2-9x=7x-64

The zeros of 2x^2-9x=7x-64 are x=4+4i,x=4-4i

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2 x^{2} - 9 x = 7 x - 64

x = 4 + 4 i, x = 4 - 4 i

Solution steps

2 x^{2} - 9 x = 7 x - 64

Move

64

to the left side

2 x^{2} - 9 x + 64 = 7 x

Move

7 x

to the left side

2 x^{2} - 16 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 2 \cdot 64}{2 \cdot 2}

Simplify

(- 16)^{2} - 4 \cdot 2 \cdot 64 : 16 i

x_{1, 2} = \frac{- ( - 16 ) \pm 16 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 16 i}{2 \cdot 2}, x_{2} = \frac{- ( - 16 ) - 16 i}{2 \cdot 2}

x = \frac{- ( - 16 ) + 16 i}{2 \cdot 2} : 4 + 4 i

x = \frac{- ( - 16 ) - 16 i}{2 \cdot 2} : 4 - 4 i

The solutions to the quadratic equation are:

x = 4 + 4 i, x = 4 - 4 i

x^{2} - 4 x - 46 = 0

1^{2} + y^{2} = 1 + 8 y

x^{2} + 0.2 x + 9.01 = 0

x, 2 x^{2} - 4 x + 1 = 0

192 = - 16 t^{2} + 112 t

What are the solutions to the equation 2x^2-9x=7x-64 ?
The solutions to the equation 2x^2-9x=7x-64 are x=4+4i,x=4-4i
Find the zeros of 2x^2-9x=7x-64
The zeros of 2x^2-9x=7x-64 are x=4+4i,x=4-4i