What are the solutions to the equation solvefor x,3x^2+6x+2=0 ?

The solutions to the equation solvefor x,3x^2+6x+2=0 are x=(-3+sqrt(3))/3 ,x=-(sqrt(3)+1)/(sqrt(3))

Find the zeros of solvefor x,3x^2+6x+2=0

The zeros of solvefor x,3x^2+6x+2=0 are x=(-3+sqrt(3))/3 ,x=-(sqrt(3)+1)/(sqrt(3))

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x, 3 x^{2} + 6 x + 2 = 0

x = \frac{- 3 + 3}{3}, x = - \frac{3 + 1}{3}

Decimal Notation

x = - 0.42264 \dots, x = - 1.57735 \dots

Solution steps

3 x^{2} + 6 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

6^{2} - 4 \cdot 3 \cdot 2 = 23

x_{1, 2} = \frac{- 6 \pm 2 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 2 3}{2 \cdot 3}, x_{2} = \frac{- 6 - 2 3}{2 \cdot 3}

x = \frac{- 6 + 2 3}{2 \cdot 3} : \frac{- 3 + 3}{3}

x = \frac{- 6 - 2 3}{2 \cdot 3} : - \frac{3 + 1}{3}

The solutions to the quadratic equation are:

x = \frac{- 3 + 3}{3}, x = - \frac{3 + 1}{3}

x^{(2)} - 4 x + 10 = 0

5 (x^{2} - 6 x) + 13 = - 4 (x - 2)

5 x^{2} + 8 = - 4 x

n^{2} - 14 n + 40 = 0

x^{2} - 10 x - 11 = 0

What are the solutions to the equation solvefor x,3x^2+6x+2=0 ?
The solutions to the equation solvefor x,3x^2+6x+2=0 are x=(-3+sqrt(3))/3 ,x=-(sqrt(3)+1)/(sqrt(3))
Find the zeros of solvefor x,3x^2+6x+2=0
The zeros of solvefor x,3x^2+6x+2=0 are x=(-3+sqrt(3))/3 ,x=-(sqrt(3)+1)/(sqrt(3))