What are the solutions to the equation x^2=-2+3x ?

The solutions to the equation x^2=-2+3x are x=2,x=1

Find the zeros of x^2=-2+3x

The zeros of x^2=-2+3x are x=2,x=1

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x^{2} = - 2 + 3 x

x = 2, x = 1

Solution steps

x^{2} = - 2 + 3 x

Move

3 x

to the left side

x^{2} - 3 x = - 2

Move

2

to the left side

x^{2} - 3 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 2 = 1

x_{1, 2} = \frac{- ( - 3 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 1}{2 \cdot 1}

x = \frac{- ( - 3 ) + 1}{2 \cdot 1} : 2

x = \frac{- ( - 3 ) - 1}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 2, x = 1

x, 3 x^{2} + 3 y^{2} + a x = 0

x (3 x + 11) - 20 = 0

x^{2} - 3 x + 5 = 0

x^{2} + 8 x = - 65

y^{2} + 16 y + 39 = 0

What are the solutions to the equation x^2=-2+3x ?
The solutions to the equation x^2=-2+3x are x=2,x=1
Find the zeros of x^2=-2+3x
The zeros of x^2=-2+3x are x=2,x=1