What are the solutions to the equation -10x^2=3x^2-3 ?

The solutions to the equation -10x^2=3x^2-3 are x=sqrt(3/13),x=-sqrt(3/13)

Find the zeros of -10x^2=3x^2-3

The zeros of -10x^2=3x^2-3 are x=sqrt(3/13),x=-sqrt(3/13)

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- 10 x^{2} = 3 x^{2} - 3

x = \frac{3}{13}, x = - \frac{3}{13}

Decimal Notation

x = 0.48038 \dots, x = - 0.48038 \dots

Solution steps

- 10 x^{2} = 3 x^{2} - 3

Move

3 x^{2}

to the left side

- 13 x^{2} = - 3

Divide both sides by

- 13

x^{2} = \frac{3}{13}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{3}{13}, x = - \frac{3}{13}

2 (s + 1)^{2} - 5 (s + 1) - 3 = 0

x^{2} = 8^{2} + (- 15)^{2}

(- 2 - x) (1 - x) + 10 = 0

x^{2} + 85 = 20 x

x^{2} + 3 x - 1 = 4 x + 2

What are the solutions to the equation -10x^2=3x^2-3 ?
The solutions to the equation -10x^2=3x^2-3 are x=sqrt(3/13),x=-sqrt(3/13)
Find the zeros of -10x^2=3x^2-3
The zeros of -10x^2=3x^2-3 are x=sqrt(3/13),x=-sqrt(3/13)