What are the solutions to the equation 2w^2+3=-7w ?

The solutions to the equation 2w^2+3=-7w are w=-1/2 ,w=-3

Find the zeros of 2w^2+3=-7w

The zeros of 2w^2+3=-7w are w=-1/2 ,w=-3

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2 w^{2} + 3 = - 7 w

w = - \frac{1}{2}, w = - 3

Decimal Notation

w = - 0.5, w = - 3

Solution steps

2 w^{2} + 3 = - 7 w

Move

7 w

to the left side

2 w^{2} + 3 + 7 w = 0

Write in the standard form

a x^{2} + b x + c = 0

2 w^{2} + 7 w + 3 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

7^{2} - 4 \cdot 2 \cdot 3 = 5

w_{1, 2} = \frac{- 7 \pm 5}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- 7 + 5}{2 \cdot 2}, w_{2} = \frac{- 7 - 5}{2 \cdot 2}

w = \frac{- 7 + 5}{2 \cdot 2} : - \frac{1}{2}

w = \frac{- 7 - 5}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

w = - \frac{1}{2}, w = - 3

x, x^{2} + 6 x - 27 = 0

x, 2 x^{2} - 4 x + 3 = 0

u^{2} + 4 = 0

x, 3 x^{2} - 2 y^{3} D x y = 0

x^{2} - 10 x + 25 = 25

What are the solutions to the equation 2w^2+3=-7w ?
The solutions to the equation 2w^2+3=-7w are w=-1/2 ,w=-3
Find the zeros of 2w^2+3=-7w
The zeros of 2w^2+3=-7w are w=-1/2 ,w=-3