What are the solutions to the equation x^2-4x+23=0 ?

The solutions to the equation x^2-4x+23=0 are x=2+sqrt(19)i,x=2-sqrt(19)i

Find the zeros of x^2-4x+23=0

The zeros of x^2-4x+23=0 are x=2+sqrt(19)i,x=2-sqrt(19)i

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x^{2} - 4 x + 23 = 0

x = 2 + 19 i, x = 2 - 19 i

Solution steps

x^{2} - 4 x + 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 23}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 23 : 219 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 19 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 19 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 19 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 19 i}{2 \cdot 1} : 2 + 19 i

x = \frac{- ( - 4 ) - 2 19 i}{2 \cdot 1} : 2 - 19 i

The solutions to the quadratic equation are:

x = 2 + 19 i, x = 2 - 19 i

\frac{7 - i}{4}

\frac{x ^{\frac{3}{5}}}{x ^{\frac{3}{10}}}

4 (\frac{π}{4})

5 \cdot 6

7 w^{2} - 56 = 0

What are the solutions to the equation x^2-4x+23=0 ?
The solutions to the equation x^2-4x+23=0 are x=2+sqrt(19)i,x=2-sqrt(19)i
Find the zeros of x^2-4x+23=0
The zeros of x^2-4x+23=0 are x=2+sqrt(19)i,x=2-sqrt(19)i