What are the solutions to the equation x^2-(-5)x+6=0 ?

The solutions to the equation x^2-(-5)x+6=0 are x=-2,x=-3

Find the zeros of x^2-(-5)x+6=0

The zeros of x^2-(-5)x+6=0 are x=-2,x=-3

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x^{2} - (- 5) x + 6 = 0

x = - 2, x = - 3

Solution steps

x^{2} - (- 5) x + 6 = 0

Refine

x^{2} + 5 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 6 = 1

x_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 1}{2 \cdot 1}, x_{2} = \frac{- 5 - 1}{2 \cdot 1}

x = \frac{- 5 + 1}{2 \cdot 1} : - 2

x = \frac{- 5 - 1}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = - 2, x = - 3

a^{2} = 900

2 x (x - 3) - 4 (x - 3) = 0

5 l^{2} - 3 l + 2 = 0

x, f (x + 2) = x^{2} + 1

(x - 2) (x + 4) = 2 x

What are the solutions to the equation x^2-(-5)x+6=0 ?
The solutions to the equation x^2-(-5)x+6=0 are x=-2,x=-3
Find the zeros of x^2-(-5)x+6=0
The zeros of x^2-(-5)x+6=0 are x=-2,x=-3