What are the solutions to the equation 3r^2=-48r ?

The solutions to the equation 3r^2=-48r are r=0,r=-16

Find the zeros of 3r^2=-48r

The zeros of 3r^2=-48r are r=0,r=-16

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3 r^{2} = - 48 r

r = 0, r = - 16

Solution steps

3 r^{2} = - 48 r

Move

48 r

to the left side

3 r^{2} + 48 r = 0

Factor

3 r^{2} + 48 r : 3 r (r + 16)

3 r (r + 16) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

r = 0 or r + 16 = 0

Solve

r + 16 = 0 : r = - 16

The solutions to the quadratic equation are:

r = 0, r = - 16

2 x^{2} + 4 x - 2

2 x^{2} + 4 x - 7

3 x^{2} - 6 = 4

a^{2} - 144 = 0

4 x^{2} - 12 x = 0

What are the solutions to the equation 3r^2=-48r ?
The solutions to the equation 3r^2=-48r are r=0,r=-16
Find the zeros of 3r^2=-48r
The zeros of 3r^2=-48r are r=0,r=-16