What are the solutions to the equation 3a^2+10a+8=0 ?

The solutions to the equation 3a^2+10a+8=0 are a=-4/3 ,a=-2

Find the zeros of 3a^2+10a+8=0

The zeros of 3a^2+10a+8=0 are a=-4/3 ,a=-2

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3 a^{2} + 10 a + 8 = 0

a = - \frac{4}{3}, a = - 2

Decimal Notation

a = - 1.33333 \dots, a = - 2

Solution steps

3 a^{2} + 10 a + 8 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 \cdot 8}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 \cdot 8 = 2

a_{1, 2} = \frac{- 10 \pm 2}{2 \cdot 3}

Separate the solutions

a_{1} = \frac{- 10 + 2}{2 \cdot 3}, a_{2} = \frac{- 10 - 2}{2 \cdot 3}

a = \frac{- 10 + 2}{2 \cdot 3} : - \frac{4}{3}

a = \frac{- 10 - 2}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

a = - \frac{4}{3}, a = - 2

x^{2} - 9 x - 77 = 0

(x + 2) (x - 5) = 8

2 x^{2} + 3 x = - 4

2 x^{2} + 3 x = 5 x

3 x^{2} + 7 = 28

What are the solutions to the equation 3a^2+10a+8=0 ?
The solutions to the equation 3a^2+10a+8=0 are a=-4/3 ,a=-2
Find the zeros of 3a^2+10a+8=0
The zeros of 3a^2+10a+8=0 are a=-4/3 ,a=-2