What are the solutions to the equation (x+2)(x-2)+x^2+6=0 ?

The solutions to the equation (x+2)(x-2)+x^2+6=0 are x=i,x=-i

Find the zeros of (x+2)(x-2)+x^2+6=0

The zeros of (x+2)(x-2)+x^2+6=0 are x=i,x=-i

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(x + 2) (x - 2) + x^{2} + 6 = 0

x = i, x = - i

Solution steps

(x + 2) (x - 2) + x^{2} + 6 = 0

Expand

(x + 2) (x - 2) + x^{2} + 6 : 2 x^{2} + 2

2 x^{2} + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

Simplify

0^{2} - 4 \cdot 2 \cdot 2 : 4 i

x_{1, 2} = \frac{- 0 \pm 4 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 0 + 4 i}{2 \cdot 2}, x_{2} = \frac{- 0 - 4 i}{2 \cdot 2}

x = \frac{- 0 + 4 i}{2 \cdot 2} : i

x = \frac{- 0 - 4 i}{2 \cdot 2} : - i

The solutions to the quadratic equation are:

x = i, x = - i

x^{2} = - 1, x^{1} = 6

3 x^{2} - 9 x = - 6

24 x^{2} - 10 = 0

(v - 3)^{2} - 5 = 0

5 x^{2} - 2 x + 18 = 0

What are the solutions to the equation (x+2)(x-2)+x^2+6=0 ?
The solutions to the equation (x+2)(x-2)+x^2+6=0 are x=i,x=-i
Find the zeros of (x+2)(x-2)+x^2+6=0
The zeros of (x+2)(x-2)+x^2+6=0 are x=i,x=-i