What are the solutions to the equation (x-1)^2-8x-8-9=0 ?

The solutions to the equation (x-1)^2-8x-8-9=0 are x=5+sqrt(41),x=5-sqrt(41)

Find the zeros of (x-1)^2-8x-8-9=0

The zeros of (x-1)^2-8x-8-9=0 are x=5+sqrt(41),x=5-sqrt(41)

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(x - 1)^{2} - 8 x - 8 - 9 = 0

x = 5 + 41, x = 5 - 41

Decimal Notation

x = 11.40312 \dots, x = - 1.40312 \dots

Solution steps

(x - 1)^{2} - 8 x - 8 - 9 = 0

Expand

(x - 1)^{2} - 8 x - 8 - 9 : x^{2} - 10 x - 16

x^{2} - 10 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 16) = 241

x_{1, 2} = \frac{- ( - 10 ) \pm 2 41}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 41}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 41}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 41}{2 \cdot 1} : 5 + 41

x = \frac{- ( - 10 ) - 2 41}{2 \cdot 1} : 5 - 41

The solutions to the quadratic equation are:

x = 5 + 41, x = 5 - 41

z^{2} - 7 z - 7 = 0

2 z^{2} - 10 z + 12 = 0

(x + 2)^{2} + 6 = 0

x^{2} + 56 = 15 x

6 (v + 3)^{2} - 1 = 5

What are the solutions to the equation (x-1)^2-8x-8-9=0 ?
The solutions to the equation (x-1)^2-8x-8-9=0 are x=5+sqrt(41),x=5-sqrt(41)
Find the zeros of (x-1)^2-8x-8-9=0
The zeros of (x-1)^2-8x-8-9=0 are x=5+sqrt(41),x=5-sqrt(41)