What are the solutions to the equation 0=3x^2-2x+9 ?

The solutions to the equation 0=3x^2-2x+9 are x= 1/3+i(sqrt(26))/3 ,x= 1/3-i(sqrt(26))/3

Find the zeros of 0=3x^2-2x+9

The zeros of 0=3x^2-2x+9 are x= 1/3+i(sqrt(26))/3 ,x= 1/3-i(sqrt(26))/3

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0 = 3 x^{2} - 2 x + 9

x = \frac{1}{3} + i \frac{26}{3}, x = \frac{1}{3} - i \frac{26}{3}

Solution steps

0 = 3 x^{2} - 2 x + 9

Switch sides

3 x^{2} - 2 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 \cdot 9}{2 \cdot 3}

Simplify

(- 2)^{2} - 4 \cdot 3 \cdot 9 : 226 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 26 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 26 i}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 2 26 i}{2 \cdot 3}

x = \frac{- ( - 2 ) + 2 26 i}{2 \cdot 3} : \frac{1}{3} + i \frac{26}{3}

x = \frac{- ( - 2 ) - 2 26 i}{2 \cdot 3} : \frac{1}{3} - i \frac{26}{3}

The solutions to the quadratic equation are:

x = \frac{1}{3} + i \frac{26}{3}, x = \frac{1}{3} - i \frac{26}{3}

z^{2} - 7 z - 3 = 0

- 2 x^{2} - 10 x + 5 = 0

- a^{2} + a + 2 = 0

- 2 (x - 3)^{2} = 0

x^{2} + \frac{1}{2} x - 5 = 0

What are the solutions to the equation 0=3x^2-2x+9 ?
The solutions to the equation 0=3x^2-2x+9 are x= 1/3+i(sqrt(26))/3 ,x= 1/3-i(sqrt(26))/3
Find the zeros of 0=3x^2-2x+9
The zeros of 0=3x^2-2x+9 are x= 1/3+i(sqrt(26))/3 ,x= 1/3-i(sqrt(26))/3