What are the solutions to the equation y^2-6y+9=-25 ?

The solutions to the equation y^2-6y+9=-25 are y=3+5i,y=3-5i

Find the zeros of y^2-6y+9=-25

The zeros of y^2-6y+9=-25 are y=3+5i,y=3-5i

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y^{2} - 6 y + 9 = - 25

y = 3 + 5 i, y = 3 - 5 i

Solution steps

y^{2} - 6 y + 9 = - 25

Move

25

to the left side

y^{2} - 6 y + 34 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 34}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 34 : 10 i

y_{1, 2} = \frac{- ( - 6 ) \pm 10 i}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 10 i}{2 \cdot 1}, y_{2} = \frac{- ( - 6 ) - 10 i}{2 \cdot 1}

y = \frac{- ( - 6 ) + 10 i}{2 \cdot 1} : 3 + 5 i

y = \frac{- ( - 6 ) - 10 i}{2 \cdot 1} : 3 - 5 i

The solutions to the quadratic equation are:

y = 3 + 5 i, y = 3 - 5 i

3 x^{2} - 2 x + 1

3 (x - 2)^{2} - 8 = 19

(x - 8) (x + 4) = 1

x^{2} - 15 x + 49 = 0

(0.3 - x) (1.5 - x) + 0.9 (0.375) = 0

What are the solutions to the equation y^2-6y+9=-25 ?
The solutions to the equation y^2-6y+9=-25 are y=3+5i,y=3-5i
Find the zeros of y^2-6y+9=-25
The zeros of y^2-6y+9=-25 are y=3+5i,y=3-5i