What are the solutions to the equation x^2-18x-81=-161 ?

The solutions to the equation x^2-18x-81=-161 are x=10,x=8

Find the zeros of x^2-18x-81=-161

The zeros of x^2-18x-81=-161 are x=10,x=8

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x^{2} - 18 x - 81 = - 161

x = 10, x = 8

Solution steps

x^{2} - 18 x - 81 = - 161

Move

161

to the left side

x^{2} - 18 x + 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 80}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 80 = 2

x_{1, 2} = \frac{- ( - 18 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 2}{2 \cdot 1}

x = \frac{- ( - 18 ) + 2}{2 \cdot 1} : 10

x = \frac{- ( - 18 ) - 2}{2 \cdot 1} : 8

The solutions to the quadratic equation are:

x = 10, x = 8

x^{2} - 10 x + 7

4 d^{2} - d - 3 = - d^{2}

2 x^{2} - x - 10 = 0

(x) = x^{2} - 6 x + 8

(k + 2) x^{2} + 2 k x + k + 1 = 0

What are the solutions to the equation x^2-18x-81=-161 ?
The solutions to the equation x^2-18x-81=-161 are x=10,x=8
Find the zeros of x^2-18x-81=-161
The zeros of x^2-18x-81=-161 are x=10,x=8