What are the solutions to the equation 11r^2-15r=-4 ?

The solutions to the equation 11r^2-15r=-4 are r=1,r= 4/11

Find the zeros of 11r^2-15r=-4

The zeros of 11r^2-15r=-4 are r=1,r= 4/11

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11 r^{2} - 15 r = - 4

r = 1, r = \frac{4}{11}

Decimal

r = 1, r = 0.36363 \dots

Solution steps

11 r^{2} - 15 r = - 4

Move

4

to the left side

11 r^{2} - 15 r + 4 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 11 \cdot 4}{2 \cdot 11}

(- 15)^{2} - 4 \cdot 11 \cdot 4 = 7

r_{1, 2} = \frac{- ( - 15 ) \pm 7}{2 \cdot 11}

Separate the solutions

r_{1} = \frac{- ( - 15 ) + 7}{2 \cdot 11}, r_{2} = \frac{- ( - 15 ) - 7}{2 \cdot 11}

r = \frac{- ( - 15 ) + 7}{2 \cdot 11} : 1

r = \frac{- ( - 15 ) - 7}{2 \cdot 11} : \frac{4}{11}

The solutions to the quadratic equation are:

r = 1, r = \frac{4}{11}

5 x^{2} - 10 = 70

3 (x - 5)^{2} = 27

7 x^{2} - 9 x - 8 = 0

x^{2} + 2 x + \frac{1}{2} = 0

(4 x - 1)^{2} = 27

What are the solutions to the equation 11r^2-15r=-4 ?
The solutions to the equation 11r^2-15r=-4 are r=1,r= 4/11
Find the zeros of 11r^2-15r=-4
The zeros of 11r^2-15r=-4 are r=1,r= 4/11