What are the solutions to the equation (5-2x)^2-16=0 ?

The solutions to the equation (5-2x)^2-16=0 are x= 1/2 ,x= 9/2

Find the zeros of (5-2x)^2-16=0

The zeros of (5-2x)^2-16=0 are x= 1/2 ,x= 9/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(5 - 2 x)^{2} - 16 = 0

x = \frac{1}{2}, x = \frac{9}{2}

Decimal

x = 0.5, x = 4.5

Solution steps

(5 - 2 x)^{2} - 16 = 0

Move

16

to the right side

(5 - 2 x)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 - 2 x = 16 : x = \frac{1}{2}

Solve

5 - 2 x = - 16 : x = \frac{9}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = \frac{9}{2}

3 b^{2} - 4 b + 1 = 0

x^{2} - 20 x + 40 = - 20

14 x + 15 x^{2} = 8

5 x^{2} + 11 x = 12

100 = x (20 - x)

What are the solutions to the equation (5-2x)^2-16=0 ?
The solutions to the equation (5-2x)^2-16=0 are x= 1/2 ,x= 9/2
Find the zeros of (5-2x)^2-16=0
The zeros of (5-2x)^2-16=0 are x= 1/2 ,x= 9/2