What are the solutions to the equation 3x^2=5\mod 7 ?

The solutions to the equation 3x^2=5\mod 7 are x=(sqrt(35))/(sqrt(3)),x=-(sqrt(35))/(sqrt(3))

Find the zeros of 3x^2=5\mod 7

The zeros of 3x^2=5\mod 7 are x=(sqrt(35))/(sqrt(3)),x=-(sqrt(35))/(sqrt(3))

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3 x^{2} = 5 mod 7

x = \frac{35}{3}, x = - \frac{35}{3}

Solution steps

3 x^{2} = 5 mod 7

Multiply the numbers:

5 \cdot 7 = 35

3 x^{2} = 35

Divide both sides by

3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

Simplify

x = \frac{35}{3}, x = - \frac{35}{3}

2 (- 3 x + 5)^{2} - 7 = 1

a, a^{2} = b^{3}

10 0^{2} = 9 6^{2} + x^{2}

- 1.5 x = 0.1 x^{2}

5^{2} + 1^{2} = x^{2}

What are the solutions to the equation 3x^2=5\mod 7 ?
The solutions to the equation 3x^2=5\mod 7 are x=(sqrt(35))/(sqrt(3)),x=-(sqrt(35))/(sqrt(3))
Find the zeros of 3x^2=5\mod 7
The zeros of 3x^2=5\mod 7 are x=(sqrt(35))/(sqrt(3)),x=-(sqrt(35))/(sqrt(3))