What are the solutions to the equation w^2+8w+21=0 ?

The solutions to the equation w^2+8w+21=0 are w=-4+sqrt(5)i,w=-4-sqrt(5)i

Find the zeros of w^2+8w+21=0

The zeros of w^2+8w+21=0 are w=-4+sqrt(5)i,w=-4-sqrt(5)i

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w^{2} + 8 w + 21 = 0

w = - 4 + 5 i, w = - 4 - 5 i

Solution steps

w^{2} + 8 w + 21 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 21 : 25 i

w_{1, 2} = \frac{- 8 \pm 2 5 i}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 8 + 2 5 i}{2 \cdot 1}, w_{2} = \frac{- 8 - 2 5 i}{2 \cdot 1}

w = \frac{- 8 + 2 5 i}{2 \cdot 1} : - 4 + 5 i

w = \frac{- 8 - 2 5 i}{2 \cdot 1} : - 4 - 5 i

The solutions to the quadratic equation are:

w = - 4 + 5 i, w = - 4 - 5 i

(x + 4) (x - 3) = - 10

6 c^{2} - 24 = 0

25 - x^{2} = 4 x

C, E = M C^{2}

(y - 2)^{2} - 10 (y - 2) = - 9

What are the solutions to the equation w^2+8w+21=0 ?
The solutions to the equation w^2+8w+21=0 are w=-4+sqrt(5)i,w=-4-sqrt(5)i
Find the zeros of w^2+8w+21=0
The zeros of w^2+8w+21=0 are w=-4+sqrt(5)i,w=-4-sqrt(5)i