What are the solutions to the equation x^2+x-32=0 ?

The solutions to the equation x^2+x-32=0 are x=(-1+sqrt(129))/2 ,x=(-1-sqrt(129))/2

Find the zeros of x^2+x-32=0

The zeros of x^2+x-32=0 are x=(-1+sqrt(129))/2 ,x=(-1-sqrt(129))/2

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x^{2} + x - 32 = 0

x = \frac{- 1 + 129}{2}, x = \frac{- 1 - 129}{2}

Decimal Notation

x = 5.17890 \dots, x = - 6.17890 \dots

Solution steps

x^{2} + x - 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 32 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 32) = 129

x_{1, 2} = \frac{- 1 \pm 129}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 129}{2 \cdot 1}, x_{2} = \frac{- 1 - 129}{2 \cdot 1}

x = \frac{- 1 + 129}{2 \cdot 1} : \frac{- 1 + 129}{2}

x = \frac{- 1 - 129}{2 \cdot 1} : \frac{- 1 - 129}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 129}{2}, x = \frac{- 1 - 129}{2}

(2 x - 1) (x + 3) = 4

2 y^{2} + 7 y - 4 = 0

2 x^{2} + 7 x - 44 = 0

x^{2} + 8 x + 9 = 0

7 w^{2} - 4 = 0

What are the solutions to the equation x^2+x-32=0 ?
The solutions to the equation x^2+x-32=0 are x=(-1+sqrt(129))/2 ,x=(-1-sqrt(129))/2
Find the zeros of x^2+x-32=0
The zeros of x^2+x-32=0 are x=(-1+sqrt(129))/2 ,x=(-1-sqrt(129))/2