What are the solutions to the equation 0=x^2+4x-21 ?

The solutions to the equation 0=x^2+4x-21 are x=3,x=-7

Find the zeros of 0=x^2+4x-21

The zeros of 0=x^2+4x-21 are x=3,x=-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = x^{2} + 4 x - 21

x = 3, x = - 7

Solution steps

0 = x^{2} + 4 x - 21

Switch sides

x^{2} + 4 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 21 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 21) = 10

x_{1, 2} = \frac{- 4 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 10}{2 \cdot 1}, x_{2} = \frac{- 4 - 10}{2 \cdot 1}

x = \frac{- 4 + 10}{2 \cdot 1} : 3

x = \frac{- 4 - 10}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 3, x = - 7

1 0^{2} + x^{2} = 1 6^{2}

66 = \frac{t ^{2} - t}{2}

8 x^{2} - 36 = - x^{2}

6 x^{2} - 12 x - 15 = 0

x, x^{2} + y^{2} - 6 y + 25 = 0

What are the solutions to the equation 0=x^2+4x-21 ?
The solutions to the equation 0=x^2+4x-21 are x=3,x=-7
Find the zeros of 0=x^2+4x-21
The zeros of 0=x^2+4x-21 are x=3,x=-7