What are the solutions to the equation -9x^2-2x+4=0 ?

The solutions to the equation -9x^2-2x+4=0 are x=-(1+sqrt(37))/9 ,x=(sqrt(37)-1)/9

Find the zeros of -9x^2-2x+4=0

The zeros of -9x^2-2x+4=0 are x=-(1+sqrt(37))/9 ,x=(sqrt(37)-1)/9

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- 9 x^{2} - 2 x + 4 = 0

x = - \frac{1 + 37}{9}, x = \frac{37 - 1}{9}

Decimal Notation

x = - 0.78697 \dots, x = 0.56475 \dots

Solution steps

- 9 x^{2} - 2 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 9 ) \cdot 4}{2 ( - 9 )}

(- 2)^{2} - 4 (- 9) \cdot 4 = 237

x_{1, 2} = \frac{- ( - 2 ) \pm 2 37}{2 ( - 9 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 37}{2 ( - 9 )}, x_{2} = \frac{- ( - 2 ) - 2 37}{2 ( - 9 )}

x = \frac{- ( - 2 ) + 2 37}{2 ( - 9 )} : - \frac{1 + 37}{9}

x = \frac{- ( - 2 ) - 2 37}{2 ( - 9 )} : \frac{37 - 1}{9}

The solutions to the quadratic equation are:

x = - \frac{1 + 37}{9}, x = \frac{37 - 1}{9}

Q^{2} - 496.6 Q + 6666.67 = 0

r, V = \frac{4}{3} r^{2} h

0 = 6 t^{2} - 30 t + 24

4 y = y^{2}

x^{2} - 4 x + 5 = 1

What are the solutions to the equation -9x^2-2x+4=0 ?
The solutions to the equation -9x^2-2x+4=0 are x=-(1+sqrt(37))/9 ,x=(sqrt(37)-1)/9
Find the zeros of -9x^2-2x+4=0
The zeros of -9x^2-2x+4=0 are x=-(1+sqrt(37))/9 ,x=(sqrt(37)-1)/9