What are the solutions to the equation y^2+3^2=-2^2 ?

The solutions to the equation y^2+3^2=-2^2 are y=sqrt(13)i,y=-sqrt(13)i

Find the zeros of y^2+3^2=-2^2

The zeros of y^2+3^2=-2^2 are y=sqrt(13)i,y=-sqrt(13)i

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y^{2} + 3^{2} = - 2^{2}

y = 13 i, y = - 13 i

Solution steps

y^{2} + 3^{2} = - 2^{2}

Move

3^{2}

to the right side

y^{2} = - 13

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - 13, y = - - 13

- 13 = 13 i

- - 13 = - 13 i

y = 13 i, y = - 13 i

12 + 16 X

45 - 63 x

9 ∣ x - 8 ∣ - 10 < 26

4 x + \frac{5}{15} x^{2} + 7 x - 2 - 2 x + \frac{3}{12} x^{2} - 7 x - 10 - 2 x - \frac{5}{20} x^{2} - 29 x + 5 = 0

What are the solutions to the equation y^2+3^2=-2^2 ?
The solutions to the equation y^2+3^2=-2^2 are y=sqrt(13)i,y=-sqrt(13)i
Find the zeros of y^2+3^2=-2^2
The zeros of y^2+3^2=-2^2 are y=sqrt(13)i,y=-sqrt(13)i