What are the solutions to the equation (7-x)(-3-x)+26=0 ?

The solutions to the equation (7-x)(-3-x)+26=0 are x=2+i,x=2-i

Find the zeros of (7-x)(-3-x)+26=0

The zeros of (7-x)(-3-x)+26=0 are x=2+i,x=2-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(7 - x) (- 3 - x) + 26 = 0

x = 2 + i, x = 2 - i

Solution steps

(7 - x) (- 3 - x) + 26 = 0

Expand

(7 - x) (- 3 - x) + 26 : x^{2} - 4 x + 5

x^{2} - 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 5 : 2 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 i}{2 \cdot 1} : 2 + i

x = \frac{- ( - 4 ) - 2 i}{2 \cdot 1} : 2 - i

The solutions to the quadratic equation are:

x = 2 + i, x = 2 - i

3 x^{2} - 6 x + 5 = 0

2 x^{2} - 28 = x (x - 3)

2 x^{2} + 7 x - 3

a^{2} - 4 = 3 a

4 x^{2} + 27 x - 18 = 0

What are the solutions to the equation (7-x)(-3-x)+26=0 ?
The solutions to the equation (7-x)(-3-x)+26=0 are x=2+i,x=2-i
Find the zeros of (7-x)(-3-x)+26=0
The zeros of (7-x)(-3-x)+26=0 are x=2+i,x=2-i