What are the solutions to the equation 25y^2-25y+6=0 ?

The solutions to the equation 25y^2-25y+6=0 are y= 3/5 ,y= 2/5

Find the zeros of 25y^2-25y+6=0

The zeros of 25y^2-25y+6=0 are y= 3/5 ,y= 2/5

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25 y^{2} - 25 y + 6 = 0

y = \frac{3}{5}, y = \frac{2}{5}

Solution steps

25 y^{2} - 25 y + 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 25 \cdot 6}{2 \cdot 25}

(- 25)^{2} - 4 \cdot 25 \cdot 6 = 5

y_{1, 2} = \frac{- ( - 25 ) \pm 5}{2 \cdot 25}

Separate the solutions

y_{1} = \frac{- ( - 25 ) + 5}{2 \cdot 25}, y_{2} = \frac{- ( - 25 ) - 5}{2 \cdot 25}

y = \frac{- ( - 25 ) + 5}{2 \cdot 25} : \frac{3}{5}

y = \frac{- ( - 25 ) - 5}{2 \cdot 25} : \frac{2}{5}

The solutions to the quadratic equation are:

y = \frac{3}{5}, y = \frac{2}{5}

2 x^{2} - x = \frac{1}{2}

5 q^{2} = 18 q + 8

x^{2} + 7 x + 19 = 0

2 (x - 6)^{2} = 98

5 k^{2} + 6 k + 3 = 0

What are the solutions to the equation 25y^2-25y+6=0 ?
The solutions to the equation 25y^2-25y+6=0 are y= 3/5 ,y= 2/5
Find the zeros of 25y^2-25y+6=0
The zeros of 25y^2-25y+6=0 are y= 3/5 ,y= 2/5