What are the solutions to the equation 5y^2-28y+15=0 ?

The solutions to the equation 5y^2-28y+15=0 are y=5,y= 3/5

Find the zeros of 5y^2-28y+15=0

The zeros of 5y^2-28y+15=0 are y=5,y= 3/5

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5 y^{2} - 28 y + 15 = 0

y = 5, y = \frac{3}{5}

Solution steps

5 y^{2} - 28 y + 15 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 5 \cdot 15}{2 \cdot 5}

(- 28)^{2} - 4 \cdot 5 \cdot 15 = 22

y_{1, 2} = \frac{- ( - 28 ) \pm 22}{2 \cdot 5}

Separate the solutions

y_{1} = \frac{- ( - 28 ) + 22}{2 \cdot 5}, y_{2} = \frac{- ( - 28 ) - 22}{2 \cdot 5}

y = \frac{- ( - 28 ) + 22}{2 \cdot 5} : 5

y = \frac{- ( - 28 ) - 22}{2 \cdot 5} : \frac{3}{5}

The solutions to the quadratic equation are:

y = 5, y = \frac{3}{5}

24 x^{2} - 280 x + 600 = 0

x^{2} - (m^{2} - 5) x - 8 m + 3 = 0

6 + 4 x - x^{2}

\frac{x ^{2}}{3} = 27

7 x^{2} + 21 x + 14 = 0

What are the solutions to the equation 5y^2-28y+15=0 ?
The solutions to the equation 5y^2-28y+15=0 are y=5,y= 3/5
Find the zeros of 5y^2-28y+15=0
The zeros of 5y^2-28y+15=0 are y=5,y= 3/5