What are the solutions to the equation 3g^2-12g=-4 ?

The solutions to the equation 3g^2-12g=-4 are g=(2(3+sqrt(6)))/3 ,g=(2(3-sqrt(6)))/3

Find the zeros of 3g^2-12g=-4

The zeros of 3g^2-12g=-4 are g=(2(3+sqrt(6)))/3 ,g=(2(3-sqrt(6)))/3

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3 g^{2} - 12 g = - 4

g = \frac{2 ( 3 + 6 )}{3}, g = \frac{2 ( 3 - 6 )}{3}

Solution steps

3 g^{2} - 12 g = - 4

Move

4

to the left side

3 g^{2} - 12 g + 4 = 0

Solve with the quadratic formula

g_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 \cdot 4 = 46

g_{1, 2} = \frac{- ( - 12 ) \pm 4 6}{2 \cdot 3}

Separate the solutions

g_{1} = \frac{- ( - 12 ) + 4 6}{2 \cdot 3}, g_{2} = \frac{- ( - 12 ) - 4 6}{2 \cdot 3}

g = \frac{- ( - 12 ) + 4 6}{2 \cdot 3} : \frac{2 ( 3 + 6 )}{3}

g = \frac{- ( - 12 ) - 4 6}{2 \cdot 3} : \frac{2 ( 3 - 6 )}{3}

The solutions to the quadratic equation are:

g = \frac{2 ( 3 + 6 )}{3}, g = \frac{2 ( 3 - 6 )}{3}

d^{2} = 45

66 x^{2} - 55 x = 0

5 x^{2} + 8 = 0

2 x^{2} + 9 x - 1 = 0

(x - 2)^{2} - 14 = 22

What are the solutions to the equation 3g^2-12g=-4 ?
The solutions to the equation 3g^2-12g=-4 are g=(2(3+sqrt(6)))/3 ,g=(2(3-sqrt(6)))/3
Find the zeros of 3g^2-12g=-4
The zeros of 3g^2-12g=-4 are g=(2(3+sqrt(6)))/3 ,g=(2(3-sqrt(6)))/3