What are the solutions to the equation 2=3x^2-x+2 ?

The solutions to the equation 2=3x^2-x+2 are x= 1/3 ,x=0

Find the zeros of 2=3x^2-x+2

The zeros of 2=3x^2-x+2 are x= 1/3 ,x=0

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2 = 3 x^{2} - x + 2

x = \frac{1}{3}, x = 0

Solution steps

2 = 3 x^{2} - x + 2

Switch sides

3 x^{2} - x + 2 = 2

Move

2

to the left side

3 x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 1)^{2} - 4 \cdot 3 \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 3}, x_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 3}

x = \frac{- ( - 1 ) + 1}{2 \cdot 3} : \frac{1}{3}

x = \frac{- ( - 1 ) - 1}{2 \cdot 3} : 0

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = 0

x^{2} - 2.459 x + 1.5 = 0

2 x^{2} - 6 x + 1 = 0

x^{2} - (3 m - 2) x + (m^{2} - 1) = 0

(x - 4)^{2} = 14 - x (2 x + 1)

5 n^{2} = 15 - 8 n

What are the solutions to the equation 2=3x^2-x+2 ?
The solutions to the equation 2=3x^2-x+2 are x= 1/3 ,x=0
Find the zeros of 2=3x^2-x+2
The zeros of 2=3x^2-x+2 are x= 1/3 ,x=0