What are the solutions to the equation x^2+6x-(6+7)=0 ?

The solutions to the equation x^2+6x-(6+7)=0 are x=-3+sqrt(22),x=-3-sqrt(22)

Find the zeros of x^2+6x-(6+7)=0

The zeros of x^2+6x-(6+7)=0 are x=-3+sqrt(22),x=-3-sqrt(22)

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x^{2} + 6 x - (6 + 7) = 0

x = - 3 + 22, x = - 3 - 22

Solution steps

x^{2} + 6 x - (6 + 7) = 0

Expand

x^{2} + 6 x - (6 + 7) : x^{2} + 6 x - 13

x^{2} + 6 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 13 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 13) = 222

x_{1, 2} = \frac{- 6 \pm 2 22}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 22}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 22}{2 \cdot 1}

x = \frac{- 6 + 2 22}{2 \cdot 1} : - 3 + 22

x = \frac{- 6 - 2 22}{2 \cdot 1} : - 3 - 22

The solutions to the quadratic equation are:

x = - 3 + 22, x = - 3 - 22

3 x^{2} - 6 x - 1

9 x^{2} + 16 x = 0

x (2 x - 1) - 3 (x - 5) = (3 x - 1) (2 + x) - 5

(1.2)^{2} + x^{2} = 1. 8^{2}

- 3 x (x + 5) = 0

What are the solutions to the equation x^2+6x-(6+7)=0 ?
The solutions to the equation x^2+6x-(6+7)=0 are x=-3+sqrt(22),x=-3-sqrt(22)
Find the zeros of x^2+6x-(6+7)=0
The zeros of x^2+6x-(6+7)=0 are x=-3+sqrt(22),x=-3-sqrt(22)