What are the solutions to the equation x^2-2x-1=-1 ?

The solutions to the equation x^2-2x-1=-1 are x=2,x=0

Find the zeros of x^2-2x-1=-1

The zeros of x^2-2x-1=-1 are x=2,x=0

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x^{2} - 2 x - 1 = - 1

x = 2, x = 0

Solution steps

x^{2} - 2 x - 1 = - 1

Move

1

to the left side

x^{2} - 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot 0 = 2

x_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2}{2 \cdot 1} : 2

x = \frac{- ( - 2 ) - 2}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 2, x = 0

2 q^{2} + q - 1596 = 0

x, T (x) = x^{2} + 30 x + 200

x^{2} + 2 x + (- 15) = 0

2 x^{2} + x = 5

5 x^{2} + 400 = 0

What are the solutions to the equation x^2-2x-1=-1 ?
The solutions to the equation x^2-2x-1=-1 are x=2,x=0
Find the zeros of x^2-2x-1=-1
The zeros of x^2-2x-1=-1 are x=2,x=0