What are the solutions to the equation 25-16x^2=0 ?

The solutions to the equation 25-16x^2=0 are x= 5/4 ,x=-5/4

Find the zeros of 25-16x^2=0

The zeros of 25-16x^2=0 are x= 5/4 ,x=-5/4

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25 - 16 x^{2} = 0

x = \frac{5}{4}, x = - \frac{5}{4}

Solution steps

25 - 16 x^{2} = 0

Move

25

to the right side

- 16 x^{2} = - 25

Divide both sides by

- 16

x^{2} = \frac{25}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{25}{16}, x = - \frac{25}{16}

\frac{25}{16} = \frac{5}{4}

- \frac{25}{16} = - \frac{5}{4}

x = \frac{5}{4}, x = - \frac{5}{4}

x, p = 3 (y + 2 x)^{2}

x, 3 x^{2} y = 75

4 x^{2} + 16 x + 8

3 x^{2} - 68 = 2 x^{2} + 6 x + 11

z^{2} - 14 z + 49 = - 121

What are the solutions to the equation 25-16x^2=0 ?
The solutions to the equation 25-16x^2=0 are x= 5/4 ,x=-5/4
Find the zeros of 25-16x^2=0
The zeros of 25-16x^2=0 are x= 5/4 ,x=-5/4