What are the solutions to the equation 0.3x^2-1.2x-0.3=0 ?

The solutions to the equation 0.3x^2-1.2x-0.3=0 are x=2+sqrt(5),x=2-sqrt(5)

Find the zeros of 0.3x^2-1.2x-0.3=0

The zeros of 0.3x^2-1.2x-0.3=0 are x=2+sqrt(5),x=2-sqrt(5)

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0.3 x^{2} - 1.2 x - 0.3 = 0

x = 2 + 5, x = 2 - 5

Decimal Notation

x = 4.23606 \dots, x = - 0.23606 \dots

Solution steps

0.3 x^{2} - 1.2 x - 0.3 = 0

Multiply both sides by

10

3 x^{2} - 12 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 (- 3) = 65

x_{1, 2} = \frac{- ( - 12 ) \pm 6 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6 5}{2 \cdot 3}, x_{2} = \frac{- ( - 12 ) - 6 5}{2 \cdot 3}

x = \frac{- ( - 12 ) + 6 5}{2 \cdot 3} : 2 + 5

x = \frac{- ( - 12 ) - 6 5}{2 \cdot 3} : 2 - 5

The solutions to the quadratic equation are:

x = 2 + 5, x = 2 - 5

\frac{3}{8} x^{2} + 3 x + 24 = 0

x, x^{2} y - x^{2} - y = 0

4 x^{2} - 32 x + 8 = 12

5 x - x^{2} - x = 0

x^{2} - 20 x + 4 = 0

What are the solutions to the equation 0.3x^2-1.2x-0.3=0 ?
The solutions to the equation 0.3x^2-1.2x-0.3=0 are x=2+sqrt(5),x=2-sqrt(5)
Find the zeros of 0.3x^2-1.2x-0.3=0
The zeros of 0.3x^2-1.2x-0.3=0 are x=2+sqrt(5),x=2-sqrt(5)